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00:00 - 00:59 | so the question is find the values of K for which K + 1 into x square minus 2 into 3 Cube + 1 into X + 8 + 1 equal to zero has real and equal roots OK so the condition for real and equal side is displacement value is equal to zero which means we square - 4ac equal to zero divisor quotient of x is equal to x square and C is the cost at OK - of 2 into 3 ke plus one value of a is K + 1 and the value of C is 8k + ok now we put these values of A B and C in the above equation is b square - 4ac so this becomes minus 2 into 3 k + 1 whole square minus 4 into K + 1 into 8k + 1 = 20 reviews of a + b whole square which is a square + b square + 2 AV so4 into |

01:00 - 01:59 | pk + 1 whole square minus 4 Y + 4 into 8k + 1 equal to zero x 4 in 29 K square + 1 + 6 ke -32 K square + 4 k + 32 K + 4 = 20 now this is 36 K square + 4 + 24k -32 K square - 32 + 36 - 36 ke - 4 = 0 9 hair if you see this term 36k square - 32 K square is work a square now class 4 - 4 x 4 24k -36 case -12 K = 20 take a common so into four k - 12 |

02:00 - 02:59 | ok from where we get two values of K HSK cause you and four k - 12 = 20 or 4K equals to 12V gate ke question 12 by 4 which is equals to 3 so we get value of k which is 0 and 1 123 thank you |

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