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`A=B + npi, n int l``A=B-npi, n int l``A=2npi + B, n int I``A= npi -B, n int l`

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00:00 - 00:59 | welcome to download this is the question if sin is equal to sin and cos A is equal to cos B then which of the following is correct option want is equal to b + and Pi for all values of and belonging to the option to a is equal to b minus and Pi for all values of N belonging to L option 3 is equal to 2 and 5 + b for all values of and belonging to I an option for a is equal to N Pi Plus and minus b for all values of N belonging to L so now we have sin a is equal to Sin B and cause a is equal to cos B to transpose it so I get Sin A minus sin b is equal to zero and cause a minus cos b is equal to zero transport |

01:00 - 01:59 | so here I can see an identity of Sin A minus Sin B which is what what is Sin A minus Sin B it is to Cos A + B by 2 Sin A minus B by 2 and what is cos A minus cos B cos A minus cos B is minus 2 Sin A + B by 2 Sin A minus b by correct sunao just use these formulas and we can see that Sin A minus B by 2 is the common factor this is the common factor in both the formulas correct so now we can use this so a minus b b to a minus b by 2 is equal to N Pi correct |

02:00 - 02:59 | sunao to transpose it because this should be the solution so a minus b would be equal to 2 and 5 and I I can see in the options that I have to find each and every each answer per aap to find or rather I have to find the answer in terms of a would be equal to 2 and + b for all values of unbelonging L or Z let me check which option is the most suitable want it is option number 3 which is a is equal to 2 and a + b for all values of N belonging to I I hope you understood the explanation thank you |

**Trigonometric equations and their solutions**

**(i) Prove that general solution of `sintheta=0` is given by `theta=npi; n in Z` (ii) Prove that general solution of `costheta=0` is `theta=((2n+1)pi/2); n in Z`**

**(iii)Prove that general solution of `tan theta=0` is `theta=npi; n in Z` (iv)Prove that the general solution of `cot theta=0` is `theta=(2n+1)pi/2, n in Z`**

**Prove that general solution of `sintheta=sin alpha` is given by `theta=npi+(-1)^n alpha, n in Z`**

**Find the general solution of the equations (i)`sin theta= sqrt3/2` (ii) `2sintheta+1=0` (iii)`cosectheta=2`**

**Prove that the general solution of `costheta=cosalpha`is given by `theta=2npipmalpha`; where `n inZ`**

**Find the general solution of the equation (i)`costheta=1/2 (ii) cos3theta=-1/2 (iii)sqrt3sec2theta=2`**

**Prove that general solution of `tan theta= tan alpha` is given by `theta=npi+alpha;n in Z`**

**Find the general solution of (i) `tan theta=1/sqrt3` (ii) `tan2theta=sqrt3` (iii)`tan3theta=-1`**

**General solution of `(i) sin^2theta = sin^2alpha; (ii) cos^2 theta = cos^2 alpha (iii) tan^2 theta = tan^2 alpha`**